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determine the number of scores that lie above the 75th percentile.

Question

determine the number of scores that lie above the 75th percentile.

Explanation:

Response
  1. Explanation:
  • Step 1: Recall the definition of percentile

The \(p\) -th percentile of a data - set divides the data into two parts. The \(p\) -th percentile is a value such that \(p\%\) of the data lies at or below it, and \((100 - p)\%\) of the data lies above it.

  • Step 2: Calculate the percentage of scores above the 75th percentile

Given \(p = 75\), the percentage of scores above the 75th percentile is \(100-75=25\%\). But to find the actual number of scores above the 75th percentile, we need to know the total number of scores \(n\) in the data - set. Let the total number of scores be \(n\). Then the number of scores above the 75th percentile is \(0.25n\). Since we are not given the value of \(n\), if we assume the total number of scores is \(n\), the proportion of scores above the 75th percentile is \(25\%\) of \(n\).

  1. Answer:

If the total number of scores is \(n\), the number of scores above the 75th percentile is \(0.25n\). Without knowing the value of \(n\), we can only express the answer in terms of \(n\) as \(0.25n\).

Answer:

  1. Explanation:
  • Step 1: Recall the definition of percentile

The \(p\) -th percentile of a data - set divides the data into two parts. The \(p\) -th percentile is a value such that \(p\%\) of the data lies at or below it, and \((100 - p)\%\) of the data lies above it.

  • Step 2: Calculate the percentage of scores above the 75th percentile

Given \(p = 75\), the percentage of scores above the 75th percentile is \(100-75=25\%\). But to find the actual number of scores above the 75th percentile, we need to know the total number of scores \(n\) in the data - set. Let the total number of scores be \(n\). Then the number of scores above the 75th percentile is \(0.25n\). Since we are not given the value of \(n\), if we assume the total number of scores is \(n\), the proportion of scores above the 75th percentile is \(25\%\) of \(n\).

  1. Answer:

If the total number of scores is \(n\), the number of scores above the 75th percentile is \(0.25n\). Without knowing the value of \(n\), we can only express the answer in terms of \(n\) as \(0.25n\).