Question

determine the quantity of bromine atoms in 18.0 grams of hgbr₂

Explanation:

Step1: Calculate molar mass of HgBr₂

The molar mass of Hg (mercury) is approximately 200.59 g/mol, and the molar mass of Br (bromine) is approximately 79.90 g/mol. For HgBr₂, the molar mass $M = 200.59+2\times79.90= 360.39\approx360.40$ g/mol.

Step2: Calculate moles of HgBr₂

Use the formula $n=\frac{m}{M}$, where $m = 18.0$ g and $M = 360.40$ g/mol. So, $n_{HgBr_2}=\frac{18.0}{360.40}\approx0.04995\approx0.05$ mol.

Step3: Determine moles of Br atoms

In one - mole of HgBr₂, there are 2 moles of Br atoms. So, $n_{Br}=2\times n_{HgBr_2}=2\times0.04995 = 0.0999\approx0.1$ mol.

Step4: Calculate number of Br atoms

Use Avogadro's number $N_A = 6.022\times 10^{23}$ atoms/mol. The number of Br atoms $N=n_{Br}\times N_A=0.0999\times6.022\times 10^{23}\approx6.02\times10^{22}$ atoms.

Answer:

$6.02\times 10^{22}$