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determine the quantity of moles of propylene (c₃h₆) in 25.0 g of the su…

Question

determine the quantity of moles of propylene (c₃h₆) in 25.0 g of the substance. 25.0 g c₃h₆×1 mol c₃h₆/42.09 g c₃h₆=

Explanation:

Step1: Identify molar - mass of propylene

The molar mass of propylene ($C_3H_6$) is calculated as follows:
The atomic mass of $C$ is approximately $12.01\ g/mol$ and $H$ is approximately $1.01\ g/mol$. For $C_3H_6$, $M=(3\times12.01 + 6\times1.01)\ g/mol=42.09\ g/mol$.

Step2: Use the mole - mass formula

The formula to calculate the number of moles ($n$) is $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass. Given $m = 25.0\ g$ and $M = 42.09\ g/mol$, then $n=\frac{25.0\ g}{42.09\ g/mol}$.
$n=\frac{25.0}{42.09}\ mol\approx0.594\ mol$

Answer:

$0.594$