QUESTION IMAGE
Question
- determine the slope and y intercept of the equation $3x + 4y = 12$
- simplify the expression: $\frac{3y^2 - 12y}{9y - 36}$
- graph the equation: $y = -2x + 3$
- determine the slope of a line that contains the points $(1,5)$ and $(9,3)$.
- write an inequality for the following graphs
a)
b)
- a hiker walks at a contact speed of 6 miles in 2 hours. what is the rate of change? (label your answer!)
Problem 8: Determine the slope and y - intercept of the equation \(3x + 4y=12\)
Step 1: Rewrite in slope - intercept form (\(y = mx + b\))
We need to solve the equation \(3x + 4y = 12\) for \(y\).
Subtract \(3x\) from both sides: \(4y=-3x + 12\)
Then divide each term by 4: \(y=-\frac{3}{4}x + 3\)
Step 2: Identify slope and y - intercept
In the slope - intercept form \(y = mx + b\), \(m\) is the slope and \(b\) is the y - intercept.
For \(y =-\frac{3}{4}x+3\), the slope \(m =-\frac{3}{4}\) and the y - intercept \(b = 3\) (or the point \((0,3)\))
Step 1: Factor numerator and denominator
Factor the numerator: \(3y^{2}-12y=3y(y - 4)\)
Factor the denominator: \(9y-36 = 9(y - 4)=3\times3(y - 4)\)
So the expression becomes \(\frac{3y(y - 4)}{3\times3(y - 4)}\)
Step 2: Cancel common factors
We can cancel out the common factors of \(3\) and \((y - 4)\) (assuming \(y
eq4\))
\(\frac{3y(y - 4)}{3\times3(y - 4)}=\frac{y}{3}\)
Step 1: Identify slope and y - intercept
The equation is in slope - intercept form \(y=mx + b\), where \(m=-2\) (slope) and \(b = 3\) (y - intercept).
Step 2: Plot the y - intercept
The y - intercept is \((0,3)\). So we plot the point \((0,3)\) on the coordinate plane.
Step 3: Use the slope to find another point
The slope \(m=-2=\frac{-2}{1}\). From the point \((0,3)\), we move down 2 units (because the numerator of the slope is - 2) and then 1 unit to the right (because the denominator of the slope is 1). This gives us the point \((1,1)\). We can also move up 2 units and 1 unit to the left from \((0,3)\) to get the point \((-1,5)\).
Step 4: Draw the line
Draw a straight line through the points \((0,3)\), \((1,1)\) (or \((-1,5)\)) to graph the line \(y=-2x + 3\)
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Slope: \(-\frac{3}{4}\), y - intercept: \(3\) (or \((0,3)\))