Question

determining the formation of a tin nitride compound
experiment introduction
an undergraduate student designed an experiment to
determine the reaction occurring when tin is heated with excess
nitrogen gas.

as a transition metal, tin has the potential to form more than
one possible charge. this allows it to form more than one
compound with nitrogen.

which of the following are the potential products of tin
combining with nitrogen?

• sn₄n₃ and sn₂n₄
• sn₂n₃ and sn₄n₃
• sn₃n₂ and sn₃n₄

Explanation:

To solve this, we analyze the possible oxidation states of tin (Sn) and nitrogen (N). Nitrogen in nitrides typically has an oxidation state of -3. Tin can have oxidation states like +2 (Sn²⁺) and +4 (Sn⁴⁺).

For Sn²⁺:

The formula for the nitride would be determined by balancing charges. Let the formula be \( \text{Sn}_x\text{N}_y \). For \( \text{Sn}^{2+} \) and \( \text{N}^{3-} \):
\( 2x - 3y = 0 \) → \( 2x = 3y \) → The simplest ratio is \( x = 3 \), \( y = 2 \), so \( \text{Sn}_3\text{N}_2 \).

For Sn⁴⁺:

For \( \text{Sn}^{4+} \) and \( \text{N}^{3-} \):
\( 4x - 3y = 0 \) → \( 4x = 3y \) → The simplest ratio is \( x = 3 \), \( y = 4 \), so \( \text{Sn}_3\text{N}_4 \).

Now, check the options:

• Option 1: \( \text{Sn}_4\text{N}_3 \) and \( \text{Sn}_2\text{N}_4 \) – Incorrect ratios.
• Option 2: \( \text{Sn}_2\text{N}_3 \) and \( \text{Sn}_4\text{N}_3 \) – Incorrect ratios.
• Option 3: \( \text{Sn}_3\text{N}_2 \) and \( \text{Sn}_3\text{N}_4 \) – Matches the possible compounds from \( \text{Sn}^{2+} \) and \( \text{Sn}^{4+} \) with \( \text{N}^{3-} \).

Answer:

\( \text{Sn}_3\text{N}_2 \) and \( \text{Sn}_3\text{N}_4 \) (the third option: "Sn₃N₂ and Sn₃N₄")