Question

the diagram below shows two hockey pucks sliding toward each other on a flat sheet of friction - less ice. each object has a mass of 2.0 kg. object x: v = 25 m/s. object y: v = 10 m/s. after the collision, object x moves to the left at 10 m/s. knowing this, what will the velocity of object y be after the collision. speed: direction:

Explanation:

Step1: Apply conservation of momentum

The formula for conservation of momentum is $m_1u_1 + m_2u_2=m_1v_1 + m_2v_2$. Here, $m_1 = m_2=2.0\ kg$, $u_1 = 25\ m/s$, $u_2 = 0\ m/s$ (assuming object Y is initially at rest), and $v_1=- 10\ m/s$ (negative because it moves to the left).

Step2: Substitute values into the formula

$(2.0\times25)+(2.0\times0)=(2.0\times(- 10))+(2.0\times v_2)$
$50 + 0=-20 + 2v_2$

Step3: Solve for $v_2$

First, add 20 to both sides of the equation: $50 + 20=2v_2$. So, $70 = 2v_2$. Then, divide both sides by 2: $v_2=\frac{70}{2}=35\ m/s$.

Answer:

$35\ m/s$