Question

the diagram shows the plans for the triangular park. how much longer is bc than ac? (3x^2 - 25x - 12) feet (3x^2 - 5x - 12) feet (3x^2 + 5x - 4) feet (3x^2 + 25x - 4) feet done

Explanation:

Step1: Identify lengths of BC and AC

$BC=(10x + 3x^{2}-8)$ feet, $AC=(15x + 4)$ feet

Step2: Find the difference

$(10x + 3x^{2}-8)-(15x + 4)$
$=10x + 3x^{2}-8-15x - 4$
$=3x^{2}+(10x-15x)+(-8 - 4)$
$=3x^{2}-5x - 12$

Answer:

$(3x^{2}-5x - 12)$ feet