Question

different forces were applied to five balls, and each force was applied for the same amount of time. the data is in the table. if the force on ball a doubles while the time remains the same, what happens to the impulse? object force (n) time (s) impulse (n·s) ball a 50 n 1.25 62.5 ball b 60 n 1.25 75.0 ball c 70 n 1.25 87.5 ball d 80 n 1.25 100 it divides in half. it does not change. it doubles. it quadruples.

Explanation:

Step1: Recall impulse formula

The formula for impulse $J$ is $J = F\times t$, where $F$ is the force and $t$ is the time.

Step2: Analyze the change

Let the initial force on ball A be $F_1 = 50\ N$ and time $t_1=1.25\ s$, so initial impulse $J_1=F_1\times t_1$. Now the force doubles to $F_2 = 2F_1$ and time remains $t_2=t_1$. Then the new - impulse $J_2=F_2\times t_2=(2F_1)\times t_1 = 2(F_1\times t_1)=2J_1$.

Answer:

It doubles.