QUESTION IMAGE
Question
directions: find the value of x. (10x - 11)° (3x - 2)° (3x + 1)°
Step1: Recall angle - sum property of a triangle
The sum of the interior angles of a triangle is 180°. So, \((10x - 11)+(3x - 2)+(3x + 1)=180\).
Step2: Combine like - terms
\[
$$\begin{align*}
(10x+3x + 3x)+(-11-2 + 1)&=180\\
16x-12&=180
\end{align*}$$
\]
Step3: Add 12 to both sides
\[
$$\begin{align*}
16x-12 + 12&=180+12\\
16x&=192
\end{align*}$$
\]
Step4: Divide both sides by 16
\[
$$\begin{align*}
\frac{16x}{16}&=\frac{192}{16}\\
x&=12
\end{align*}$$
\]
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\(x = 12\)