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directions: label each arrow with push, pull, friction, gravity, compre…

Question

directions: label each arrow with push, pull, friction, gravity, compression, or tension. identify if the force is balanced or unbalanced and which direction it will move.
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12.

  1. as the skydiver falls, the friction (air resistance) becomes equal to the downward pull of gravity. when these two forces become equal in magnitude, what will happen to the skydiver?

Explanation:

Step1: Analyze Problem 7

For the ant: Left force $F_L = 2\,\text{N}$ (friction), Right force $F_R = 8\,\text{N}$ (pull). Net force: $F_{net} = 8 - 2 = 6\,\text{N}$ right.

Step2: Analyze Problem 8

For the dog/person: Left force $F_L = 15\,\text{N}$ (pull), Right force $F_R = 10\,\text{N}$ (pull). Net force: $F_{net} = 15 - 10 = 5\,\text{N}$ left.

Step3: Analyze Problem 9

For the piano: Right force $F_R = 30\,\text{N}$ (push), Left forces $F_L = 8 + 12 + 15 = 35\,\text{N}$ (pull/friction). Net force: $F_{net} = 35 - 30 = 5\,\text{N}$ left.

Step4: Analyze Problem 10

For the rope pullers: Left force $F_L = 15\,\text{N}$ (pull), Right force $F_R = 15\,\text{N}$ (pull). Net force: $F_{net} = 15 - 15 = 0\,\text{N}$.

Step5: Analyze Problem 11 (spring)

For the mass: Upward force $F_U = 30\,\text{N}$ (tension), Downward force $F_D = 30\,\text{N}$ (gravity). Net force: $F_{net} = 30 - 30 = 0\,\text{N}$.

Step6: Analyze Problem 12 (skydiver)

For the skydiver: Upward force $F_U = 50\,\text{N}$ (air resistance), Downward force $F_D = 150\,\text{N}$ (gravity). Net force: $F_{net} = 150 - 50 = 100\,\text{N}$ down.

Step7: Answer Problem 13

When air resistance = gravity, net force is 0, so acceleration stops.

Answer:

  1. Unbalanced forces; moves right (net force = 6N right)
  2. Unbalanced forces; moves left (net force = 5N left)
  3. Unbalanced forces; moves left (net force = 5N left)
  4. Balanced forces; no movement (net force = 0N)
  5. Balanced forces; no movement (net force = 0N)
  6. Unbalanced forces; moves down (net force = 100N down)
  7. The skydiver will stop accelerating and fall at a constant terminal velocity.