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divide: ( \begin{array}{r} square \\ 26 enclose{longdiv}{7,109} end{arr…

Question

divide:
( \begin{array}{r} square \\ 26 enclose{longdiv}{7,109} end{array} ) r ( square )
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Explanation:

Step1: Divide 71 by 26

We see how many times 26 goes into 71. \( 26\times2 = 52 \), \( 26\times3=78 \) which is too big. So we use 2. Subtract \( 26\times2 = 52 \) from 71: \( 71 - 52=19 \).

Step2: Bring down the next digit (0)

Now we have 190. Divide 190 by 26. \( 26\times7 = 182 \), \( 26\times8 = 208 \) (too big). So we use 7. Subtract \( 26\times7 = 182 \) from 190: \( 190 - 182 = 8 \).

Step3: Bring down the next digit (9)

Now we have 89. Divide 89 by 26. \( 26\times3 = 78 \), \( 26\times4 = 104 \) (too big). So we use 3. Subtract \( 26\times3 = 78 \) from 89: \( 89 - 78=11 \).

Step4: Combine the quotients

The quotients we got were 2 (from first step), 7 (from second), and 3 (from third). So the quotient is \( 273 \) and the remainder is 11. We can also check by \( 26\times273+11=26\times273 + 11=7098+11 = 7109 \), which matches the dividend.

Answer:

The quotient is \( 273 \) and the remainder is \( 11 \). So in the boxes, the first box (quotient) is \( 273 \) and the second box (remainder) is \( 11 \).