Question

drag each term to the correct location on the expression. each term can be used more than once, but not all terms will be used
completely factor this quadratic expression:
$4x^2 + 12x - 72$
$4x$ $4$ $8$ $1$ $x$ $2$ $3$ $x^2$
$\square (x - \square)(\square + 6)$

Explanation:

Step1: Factor out GCF

First, find the greatest common factor (GCF) of $4x^2$, $12x$, and $-72$. The GCF is 4.
$4x^2 + 12x - 72 = 4(x^2 + 3x - 18)$

Step2: Factor the quadratic trinomial

Factor $x^2 + 3x - 18$ by finding two numbers that multiply to $-18$ and add to $3$. These numbers are $6$ and $-3$.
$x^2 + 3x - 18 = (x - 3)(x + 6)$

Step3: Combine the factors

Substitute the factored trinomial back into the expression from Step1.
$4(x^2 + 3x - 18) = 4(x - 3)(x + 6)$

Answer:

$4(x - 3)(x + 6)$
(The blanks are filled with 4, 3, $x$ respectively)