Question

draw the image of quadrilateral abcd under a translation by 1 unit to the right and 4 units up.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated 1 unit to the right and 4 units up, the new - point is $(x + 1,y + 4)$.

Step2: Translate point A

Assume point $A=(0,0)$. After translation, $A'=(0 + 1,0 + 4)=(1,4)$.

Step3: Translate point B

If $B=(-4,3)$, then $B'=(-4 + 1,3 + 4)=(-3,7)$.

Step4: Translate point C

If $C=(5,2)$, then $C'=(5 + 1,2 + 4)=(6,6)$.

Step5: Translate point D

If $D=(6,-2)$, then $D'=(6 + 1,-2 + 4)=(7,2)$.

Step6: Draw the new quadrilateral

Plot the points $A'$, $B'$, $C'$, and $D'$ on the coordinate - plane and connect them in order to form the translated quadrilateral.

Answer:

Plot the points $(1,4)$, $(-3,7)$, $(6,6)$, and $(7,2)$ on the coordinate - plane and connect them to get the image of quadrilateral $ABCD$ under the given translation.