Question

draw a lewis structure for the molecule below, showing all lone pairs. you may abbreviate any methyl groups as $mathrm{ch_3}$.
$mathrm{h_2nch_2co_2ch_3}$
click and drag to start drawing a structure.

Explanation:

Step1: Identify atoms and bonds

The molecule is \( \ce{H2NCH2CO2CH3} \) (glycine methyl ester). Let's break down the atoms: \( \ce{N} \) (with 2 \( \ce{H} \) ), \( \ce{C} \) (methylene, \( \ce{CH2} \) ), \( \ce{C} \) (carbonyl, \( \ce{C=O} \) ), \( \ce{O} \) (ester, \( \ce{O - CH3} \) ), and the methyl group \( \ce{CH3} \).

Step2: Draw the backbone

• Start with the amino group: \( \ce{H2N -} \). The \( \ce{N} \) has a lone pair (since \( \ce{N} \) has 5 valence electrons; 3 bonds to \( \ce{H} \) and \( \ce{C} \), so 1 lone pair: \( \ce{:NH2 -} \)).
• Then the methylene group: \( \ce{-CH2 -} \) (4 bonds: \( \ce{N - CH2 -} \), and two \( \ce{H} \) ).
• Next, the carbonyl group: \( \ce{-CO -} \) ( \( \ce{C=O} \), \( \ce{C} \) is double - bonded to \( \ce{O} \), and single - bonded to \( \ce{CH2} \) and \( \ce{O} \) ). The \( \ce{O} \) in \( \ce{C=O} \) has 2 lone pairs ( \( \ce{O} \) has 6 valence electrons; 2 in the double bond, so 4 as 2 lone pairs: \( \ce{:O=} \) ).
• Then the ester oxygen: \( \ce{-O - CH3} \). The \( \ce{O} \) here has 2 lone pairs ( \( \ce{O} \) has 6 valence electrons; 1 bond to \( \ce{C} \) (carbonyl) and 1 bond to \( \ce{CH3} \), so 4 as 2 lone pairs: \( \ce{:O - CH3} \) ).
• The methyl group \( \ce{CH3} \) is bonded to the ester \( \ce{O} \), with \( \ce{C} \) bonded to 3 \( \ce{H} \) and 1 \( \ce{O} \).

The Lewis structure (text - based representation) would be:

\( \ce{H2\overset{:}{N}-CH2 - C(\overset{:}{O})=O - O - CH3} \) (with appropriate lone pairs: \( \ce{N} \) has 1 lone pair, \( \ce{C=O} \) \( \ce{O} \) has 2 lone pairs, \( \ce{O - CH3} \) \( \ce{O} \) has 2 lone pairs)

Answer:

The Lewis structure is drawn as follows (text - based for representation):

\( \ce{H_{2}\overset{:}{N}-CH_{2}-C(\overset{:}{O})=O - O - CH_{3}} \)

(In a graphical drawing, you would represent the bonds as lines, the lone pairs as pairs of dots, with \( \ce{N} \) having one lone pair, the carbonyl \( \ce{O} \) having two lone pairs, and the ester \( \ce{O} \) having two lone pairs. The atoms are connected as \( \ce{H2N - CH2 - CO - OCH3} \) with the correct lone pairs on \( \ce{N} \), \( \ce{C=O} \) \( \ce{O} \), and \( \ce{O - CH3} \) \( \ce{O} \).)