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during the analysis, 0.00905 mol h₂o is formed. calculate the amount (m…

Question

during the analysis, 0.00905 mol h₂o is formed. calculate the amount (mol) h in 0.00905 mol h₂o. 0.00905 mol h₂o formed mol 3 item attempts remaining check next (2 of 5) try another version submit answer

Explanation:

Step1: Identify hydrogen - oxygen ratio in water

In one molecule of $H_2O$, there are 2 moles of $H$ for every 1 mole of $H_2O$.

Step2: Calculate moles of H

Using the ratio, if we have 0.00905 mol of $H_2O$, then the moles of $H$ is $n_H=2\times n_{H_2O}$.
$n_H = 2\times0.00905$ mol.
$n_H=0.0181$ mol.

Answer:

0.0181