Question

for each part below, solve the equation.
(a) solve for y.
3(y - 2) - 5y = -2(y + 2)
no solution
y =
all real numbers are solutions
(b) solve for w.
4(w + 1) + w = 3(w - 2) + 2
no solution
w =
all real numbers are solutions

Explanation:

Step1: Expand all parentheses

$3y - 6 - 5y = -2y - 4$

Step2: Combine like terms on left

$-2y - 6 = -2y - 4$

Step3: Add $2y$ to both sides

$-6 = -4$
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Step1: Expand all parentheses

$4w + 4 + w = 3w - 6 + 2$

Step2: Combine like terms on both sides

$5w + 4 = 3w - 4$

Step3: Subtract $3w$ from both sides

$2w + 4 = -4$

Step4: Subtract 4 from both sides

$2w = -8$

Step5: Divide by 2

$w = \frac{-8}{2} = -4$

Answer:

(a) All real numbers are solutions
(b) $w = -4$