Question

ection. you should be completing the delta math before you attempt the assessment for the week. eos to help you work through the problems. if you would like to work through examples with me, please

$3x + 10 < -2$ or $13 < 3x + 10$

answer attempt 1 out of 2

inequality notation: $x < -4$ or $x > 1$

number line:
number line with -12, -10, -8, -6, -4, -2, 0, 2, 4, 6, 8, 10, 12; text: click and drag to plot line

submit answer

Explanation:

Step1: Solve \( 3x + 10 < -2 \)

Subtract 10 from both sides: \( 3x + 10 - 10 < -2 - 10 \)
Simplify: \( 3x < -12 \)
Divide by 3: \( \frac{3x}{3} < \frac{-12}{3} \)
Result: \( x < -4 \)

Step2: Solve \( 13 < 3x + 10 \)

Subtract 10 from both sides: \( 13 - 10 < 3x + 10 - 10 \)
Simplify: \( 3 < 3x \)
Divide by 3: \( \frac{3}{3} < \frac{3x}{3} \)
Result: \( 1 < x \) (or \( x > 1 \))

Answer:

The solution in inequality notation is \( x < -4 \) or \( x > 1 \). For the number line, plot an open circle at -4 and shade to the left, and an open circle at 1 and shade to the right.