Question

educe the radical.
\sqrt{96}
\sqrt{\square} \sqrt{\square}

Explanation:

Step1: Factor out perfect square

$\sqrt{96} = \sqrt{16 \times 6}$

Step2: Split radical into product

$\sqrt{16 \times 6} = \sqrt{16} \times \sqrt{6}$

Step3: Simplify perfect square root

$\sqrt{16} = 4$

Answer:

$\sqrt{16}\sqrt{6}$ (or simplified fully as $4\sqrt{6}$)