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Question
if an engine develops 121 hp at 82% power, what hp would be developed at 49%? (2 decimals if needed)
Step1: Find the full - power of the engine
Let the full - power of the engine be $x$ hp. We know that $82\%$ of $x$ is $121$ hp. So the equation is $0.82x = 121$. Solving for $x$, we get $x=\frac{121}{0.82}$.
$x=\frac{121}{0.82}\approx147.56$
Step2: Calculate the power at 49%
To find the power at $49\%$ of the full - power, we multiply the full - power $x$ by $0.49$. So the power $y = 0.49x$. Substitute $x\approx147.56$ into the equation, we get $y = 0.49\times147.56$.
$y=0.49\times147.56 = 72.3044\approx72.30$
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$72.30$