QUESTION IMAGE
Question
enter a number into each box to create an equation that has an infinite number of solutions.
$3(2x + 5) - x = \square x + \square$
Step1: Expand the left-hand side
$3(2x + 5) = 6x + 15$
Step2: Subtract $x$ from the result
$6x + 15 - x = 5x + 15$
Step3: Match for infinite solutions
For the equation $5x + 15 = \square x + \square$ to have infinite solutions, the coefficients and constants must be equal, so the boxes are 5 and 15.
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$5x + 15$