Question

for the equation shown below, the slope =
and the y-intercept is the
point ( , ).
$y + 19 = -9x + 19$
question 2
3 pts
for the equation shown below, the slope =
and the y-intercept is the
point ( , ).
$y + 15 = -6x - 14$

Explanation:

Step1: Rearrange to slope-intercept form

For first equation:

Isolate $y$ by subtracting 19 from both sides:
$y + 19 - 19 = -9x + 19 - 19$
$y = -9x + 0$

For second equation:

Isolate $y$ by subtracting 15 from both sides:
$y + 15 - 15 = -6x - 14 - 15$
$y = -6x - 29$

Step2: Identify slope and intercept

Slope-intercept form is $y=mx+b$, where $m$ is slope, and $y$-intercept is $(0,b)$.

For first equation:

$m=-9$, $b=0$, so $y$-intercept is $(0,0)$

For second equation:

$m=-6$, $b=-29$, so $y$-intercept is $(0,-29)$

Answer:

1. For $y + 19 = -9x + 19$:

Slope = $-9$, y-intercept point = $(0, 0)$

1. For $y + 15 = -6x - 14$:

Slope = $-6$, y-intercept point = $(0, -29)$