Question

evaluate the expression. $\frac{2^{-7}}{4^{-5}} = square$

Explanation:

Step1: Rewrite denominator as power of 2

$4^{-5} = (2^2)^{-5} = 2^{-10}$

Step2: Rewrite expression with same base

$\frac{2^{-7}}{2^{-10}}$

Step3: Apply exponent subtraction rule

$2^{-7 - (-10)} = 2^{3}$

Step4: Calculate the final value

$2^3 = 8$

Answer:

8