Question

evaluate $sigma=sqrt{np(1 - p)}$ for $n = 1527$, $p=\frac{4}{5}$. $sigma=$ (simplify your answer. type an integer or decimal rounded to one decimal place as needed.)

Explanation:

Step1: Substitute values of n and p

Substitute $n = 1527$ and $p=\frac{4}{5}$ into $\sigma=\sqrt{np(1 - p)}$. First find $1-p$:
$1 - p=1-\frac{4}{5}=\frac{1}{5}$
Then calculate $np(1 - p)$:
$np(1 - p)=1527\times\frac{4}{5}\times\frac{1}{5}=\frac{1527\times4}{25}=\frac{6108}{25}=244.32$

Step2: Calculate square - root

$\sigma=\sqrt{244.32}\approx15.6$

Answer:

$15.6$