Question

evaluate. write your answer as a whole number 4^0 · 4^-3 =

Explanation:

Step1: Use exponent rule \(a^m \cdot a^n = a^{m + n}\)

\(4^0 \cdot 4^{-3}=4^{0 + (-3)} = 4^{-3}\)

Step2: Use negative exponent rule \(a^{-n}=\frac{1}{a^n}\)

\(4^{-3}=\frac{1}{4^3}\)

Step3: Calculate \(4^3\)

\(4^3 = 4\times4\times4 = 64\)
So \(\frac{1}{4^3}=\frac{1}{64}\)

Answer:

\(\frac{1}{64}\) (But since the problem asks to write as a whole number over a whole number, and \(\frac{1}{64}\) is already in that form, the numerator is 1 and the denominator is 64)