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Question
exam 1
- an experiment revealed the empirical formula of a compound to be ch₂. in a separate experiment the molar mass of the compound was determined to be 42.2 g/mol. what is the molecular formula for this compound?
a) ch₂ b) c₂h₄ c) c₃h₆ d) c₄h₈
- the weighted average of the mass of all isotopes in a naturally occurring sample of an element is known as the:
a) atomic number b) atomic mass c) mass number d) density
- of the following elements, which is not found as diatomic molecule under normal conditions?
a) bromine b) helium c) oxygen d) iodine
- why do the names of some salts include the charge of the metal ion (as a roman numeral) while others do not?
a) because salts are covalent compounds which follow the law of multiple proportions
b) because salts always include polyatomic ions that have multiple possible charges
c) because the non-metal can have a range of negative charges
d) because the metal can form cations of more than one charge
- nickel (ni) is a(n):
a) alkali metal b) alkaline earth metal c) halogen d) transition metal
- which of the following elements will tend to form 2+ ions?
a) lithium (li) b) strontium (sr) c) oxygen (o) d) bromine (br)
- which of the following elements will tend to form 1– ions?
a) lithium (li) b) strontium (sr) c) oxygen (o) d) bromine (br)
- what is the correct formula for the compound formed between aluminum and oxygen?
a) alo₂ b) al₂o₃ c) al₃o₂ d) al₂o
- given the following chemical name, write the chemical formula for each compound. (12)
a) sodium carbonate dihydrate
b) nitrogen tribromide
c) hydrochloric acid
d) nickel(ii) bromide
e) sulfurous acid
f) ammonium sulfate
Question 8
Step1: Calculate molar mass of empirical formula
The empirical formula is \( CH_2 \). Molar mass of \( C = 12.01 \, g/mol \), molar mass of \( H = 1.008 \, g/mol \). So molar mass of \( CH_2 \) is \( 12.01 + 2\times1.008 = 14.026 \, g/mol \).
Step2: Find the ratio \( n \)
\( n=\frac{\text{Molar mass of compound}}{\text{Molar mass of empirical formula}}=\frac{42.2}{14.026}\approx3 \).
Step3: Determine molecular formula
Multiply subscripts in empirical formula by \( n \). So molecular formula is \( C_{3}H_{6} \) (since \( 1\times3 = 3 \) for \( C \) and \( 2\times3 = 6 \) for \( H \)).
Atomic number is number of protons. Atomic mass is weighted average of isotopic masses. Mass number is sum of protons and neutrons. Density is mass/volume. So the weighted average of isotopic masses is atomic mass.
Diatomic molecules under normal conditions: \( Br_2 \) (bromine), \( O_2 \) (oxygen), \( I_2 \) (iodine). Helium (\( He \)) is monatomic as it is a noble gas.
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c) \( C_3H_6 \)