QUESTION IMAGE
Question
example:
- 6.450m × 3.400m × 2.1m = 46.053 m³
2.1 has the fewest sf (the other two number each have 4 sf), so the answer should be rounded to 2 sf: 46 m³
- 0.003ml + 1.0222ml + 2.11ml = 3.135ml
2.11ml has the fewest sf (the others have 3 sf), so the answer should be rounded to 2 sf: 3.14ml
- 0.003ml × 1.0222ml × 2.11ml = 0.00646926 ml³
0.003ml has the fewest sf so the final answer is rounded to 1 sf: 0.006ml³
- 29.00g + 11.000g = 40g
29.00 has 2 sf which is the fewest sf, so the final answer must be in 2 sf: 40.00g
- 29.00g × 11.000g = 319g²
29.00g has 4 sf which is the fewest sf in the equation so the final answer is rounded to 4 sf: 319.0g²
- 16,340 g ÷ 23.42 g = 697.6942784
- 17.6 ml − 12.73 ml = 4.87ml
Step1: Solve addition (Q3)
Calculate sum first:
$0.003\ \text{mL} + 1.022\ \text{mL} + 2.11\ \text{mL} = 3.135\ \text{mL}$
Step2: Round Q3 to correct SF
2.11 mL has 3 SF (fewest), round to 3 SF:
$3.135\ \text{mL}
ightarrow 3.14\ \text{mL}$
Step3: Solve multiplication (Q4)
Calculate product first:
$0.003\ \text{mL} \times 1.022\ \text{mL} \times 2.11\ \text{mL} = 0.00646926\ \text{mL}^3$
Step4: Round Q4 to correct SF
0.003 mL has 1 SF (fewest), round to 1 SF:
$0.00646926\ \text{mL}^3
ightarrow 0.006\ \text{mL}^3$
Step5: Solve addition (Q5)
Calculate sum first:
$29.00\ \text{g} + 11.000\ \text{g} = 40.00\ \text{g}$
Step6: Round Q5 to correct SF
29.00 g has 4 SF, 11.000 g has 5 SF; round to 4 SF:
$40.00\ \text{g}$
Step7: Solve multiplication (Q6)
Calculate product first:
$29.00\ \text{g} \times 11.000\ \text{g} = 319.000\ \text{g}^2$
Step8: Round Q6 to correct SF
29.00 g has 4 SF (fewest), round to 4 SF:
$319.000\ \text{g}^2
ightarrow 319.0\ \text{g}^2$
Step9: Solve division (Q7)
Calculate quotient first:
$16340\ \text{g} \div 23.42\ \text{g} = 697.6942784$
Step10: Round Q7 to correct SF
23.42 g has 4 SF, 16340 g has 4 SF; round to 4 SF:
$697.6942784
ightarrow 697.7$
Step11: Solve subtraction (Q8)
Calculate difference first:
$17.6\ \text{mL} - 12.73\ \text{mL} = 4.87\ \text{mL}$
Step12: Round Q8 to correct SF
17.6 mL has 3 SF (fewest), round to 3 SF:
$4.87\ \text{mL}$
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- $3.14\ \text{mL}$
- $0.006\ \text{mL}^3$
- $40.00\ \text{g}$
- $319.0\ \text{g}^2$
- $697.7$
- $4.87\ \text{mL}$