Question

example 2
find the work done in pulling a luggage carrier by a 45.0 n force at an angle of 50° for a distance of 75.0 m.

Explanation:

Step1: Recall work done formula

Work done $W = F \cdot d \cdot \cos\theta$, where $F$ is applied force, $d$ is distance, $\theta$ is angle between force and displacement.

Step2: Substitute given values

$F = 45.0\ \text{N}$, $d = 75.0\ \text{m}$, $\theta = 50^\circ$
$W = 45.0 \times 75.0 \times \cos(50^\circ)$

Step3: Calculate the result

First, $\cos(50^\circ) \approx 0.6428$
$W \approx 45.0 \times 75.0 \times 0.6428 = 2170.05$

Answer:

Approximately $2170\ \text{J}$ (or $2.17 \times 10^3\ \text{J}$)