Question

exercise 4.30 - enhanced - with feedback and hints
consider the following balanced equation: 2n₂h₄(g)+n₂o₄(g)→3n₂(g)+4h₂o(g)
complete the following table showing the appropriate numbers of moles of reactants and products. if the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. if the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that forms.
mol n₂h₄ mol n₂o₄ mol n₂ mol h₂o
4

7

10

4.5

4.2

12.7
part a
complete the first row.
express your answers using one significant figure each.
view available hint(s)
mol n₂o₄, mol n₂, mol h₂o
submit
part b
complete the second row.
express your answers as integers separated by commas.
view available hint(s)
mol n₂h₄, mol n₂, mol h₂o

Explanation:

Step1: Determine mole - ratio from balanced equation

The balanced equation is $2N_2H_4(g)+N_2O_4(g)
ightarrow3N_2(g) + 4H_2O(g)$. The mole - ratios are: $n_{N_2H_4}:n_{N_2O_4}:n_{N_2}:n_{H_2O}=2:1:3:4$.

Step2: First row (given $n_{N_2H_4} = 4$ mol)

For $N_2O_4$: Using the ratio $\frac{n_{N_2H_4}}{n_{N_2O_4}}=\frac{2}{1}$, if $n_{N_2H_4} = 4$ mol, then $n_{N_2O_4}=\frac{4}{2}=2$ mol.
For $N_2$: Using the ratio $\frac{n_{N_2H_4}}{n_{N_2}}=\frac{2}{3}$, if $n_{N_2H_4} = 4$ mol, then $n_{N_2}=\frac{3\times4}{2}=6$ mol.
For $H_2O$: Using the ratio $\frac{n_{N_2H_4}}{n_{H_2O}}=\frac{2}{4}=\frac{1}{2}$, if $n_{N_2H_4} = 4$ mol, then $n_{H_2O}=8$ mol.

Answer:

2, 6, 8