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for exercises 1 - 5, use the diagram. 1. what composition of two rigid …

Question

for exercises 1 - 5, use the diagram.

  1. what composition of two rigid motions maps △abc to △abc?

for exercises 2 - 5, find the coordinates of p under each transformation. suppose the equation of line m is y = 2 and the equation of line n is x=-1.

  1. t_(-2,0)∘r_m
  2. t_(0, - 5)∘r_m
  3. t_(0,2)∘r_y - axis
  4. t_(3,0)∘r_x - axis

for exercises 6 - 12, write a rigid motion that produces each image.

  1. △abc→△def
  2. △abc→△ghj
  3. △abc→△klm
  4. △abc→△npq
  5. △abc→△rst
  6. △def→△ghj
  7. △ghj→△klm
  8. understand define the term glide reflection.
  9. apply the series of footprints can be described as a series of glide reflections. the composition of two identical glide reflections, for example, from the first step to the third, is equivalent to what rigid motion?

Explanation:

Response

1.

Step1: Recall identity motion

The identity motion (a translation by the zero - vector or a rotation by 0 degrees or a reflection over the same line twice etc.) maps a figure onto itself. For example, a translation \(T_{(0,0)}\) followed by a rotation \(R_{O,0}\) (rotation about a point \(O\) by 0 degrees) will map \(\triangle ABC\) to \(\triangle ABC\). Another example is a reflection \(r_l\) over a line \(l\) followed by the same reflection \(r_l\) again. The composition of two identity - like rigid motions will map the triangle onto itself.

Step1: First perform reflection \(r_m\)

The equation of line \(m\) is \(y = 2\). The rule for reflecting a point \((x,y)\) over the line \(y = k\) is \((x,2k - y)\). So, \(r_m(x,y)=(x,4 - y)\)

Step2: Then perform translation \(T_{(- 2,0)}\)

The rule for translation \(T_{(a,b)}\) is \((x,y)\to(x + a,y + b)\). So, \(T_{(-2,0)}(x,4 - y)=(x-2,4 - y)\)

Step1: First perform reflection \(r_m\)

The equation of line \(m\) is \(y = 2\). The rule for reflecting a point \((x,y)\) over the line \(y=k\) is \((x,2k - y)\). So, \(r_m(x,y)=(x,4 - y)\)

Step2: Then perform translation \(T_{(0,-5)}\)

The rule for translation \(T_{(a,b)}\) is \((x,y)\to(x + a,y + b)\). So, \(T_{(0,-5)}(x,4 - y)=(x,4 - y-5)=(x,-y - 1)\)

Answer:

A translation by the zero - vector followed by a rotation of 0 degrees (or other combinations of identity - like rigid motions such as two identical reflections)

  1. Let the coordinates of point \(P\) be \((x,y)\).