Question

exit ticket - unit 8 review 2
$\frac{16x^{2}+48x+20}{8x+4}$

Explanation:

Step1: Factor numerator and denominator

Factor out common terms:
Numerator: $16x^2 + 48x + 20 = 4(4x^2 + 12x + 5) = 4(2x+1)(2x+5)$
Denominator: $8x + 4 = 4(2x+1)$

Step2: Cancel common factors

Eliminate $4(2x+1)$ from numerator/denominator:
$\frac{4(2x+1)(2x+5)}{4(2x+1)} = 2x+5$ (where $x
eq -\frac{1}{2}$)

Answer:

$2x + 5$ (with the restriction $x
eq -\frac{1}{2}$)