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Question
explain how to plot a point in the rectangular coordinate system. give an example with your explanation
to plot the point (a,b) in the rectangular coordinate system, if a is positive, go |a| units from zero along the and if a is negative, go |a| units from zero along the then, if b is positive, go |b| units parallel to the and if b is negative, go |b| units parallel to the as an example, the point is plotted on the graph to the right. (type an ordered pair.)
Step1: Locate x - coordinate
If \(a\) is positive, go \(|a|\) units to the right from zero along the \(x -\)axis. If \(a\) is negative, go \(|a|\) units to the left from zero along the \(x -\)axis.
Step2: Locate y - coordinate
Then, if \(b\) is positive, go \(|b|\) units up parallel to the \(y -\)axis. If \(b\) is negative, go \(|b|\) units down parallel to the \(y -\)axis.
Step3: Example
Let's take the point \((3, - 2)\). For the \(x -\)coordinate \(a = 3\) (positive), we go 3 units to the right along the \(x -\)axis. For the \(y -\)coordinate \(b=-2\) (negative), we go 2 units down parallel to the \(y -\)axis.
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To plot the point \((a,b)\) in the rectangular coordinate system, if \(a\) is positive, go \(|a|\) units to the right from zero along the \(x -\)axis and if \(a\) is negative, go \(|a|\) units to the left from zero along the \(x -\)axis. Then, if \(b\) is positive, go \(|b|\) units up parallel to the \(y -\)axis and if \(b\) is negative, go \(|b|\) units down parallel to the \(y -\)axis. As an example, the point \((3,-2)\) is plotted.