QUESTION IMAGE
Question
an expression that contains a radical is in simplest radical form if (1) no number under a radical sign has a factor that is a perfect - square, (2) no fraction is under a radical sign, and (3) no radical sign is in the denominator.
(1) (\frac{2sqrt{3}}{5}) is in simplest radical form, because the number under the radical sign doesnt have a perfect - square factor, no fraction is under the radical sign, and no radical sign is in the denominator.
(2) (\frac{sqrt{12}}{5}) is not in simplest radical form, because the number under the radical has 4 as a factor, and 4 is a perfect square. (\frac{sqrt{12}}{5}=\frac{2sqrt{3}}{5})
(3) (\frac{3}{sqrt{5}}) is not in simplest radical form, because a fraction is under the radical sign. (\frac{3}{sqrt{5}}=\frac{3sqrt{5}}{5})
circle the numbers which are in simplest radical form.
(\frac{3sqrt{2}}{10}), (\frac{sqrt{6}}{4}), (\frac{1}{sqrt{5}}), (\frac{3sqrt{7}}{8}), (\frac{5sqrt{3}}{sqrt{7}}), (\frac{2sqrt{7}}{7}), (\frac{sqrt{8}}{3})
use the quotient rule. then simplify the numerator and denominator. circle the result if it is in simplest radical form.
(sqrt{\frac{12}{25}}=\frac{sqrt{12}}{sqrt{25}}=\frac{2sqrt{3}}{5}), (sqrt{\frac{8}{9}}=\frac{sqrt{8}}{sqrt{9}}=\frac{2sqrt{2}}{3}), (sqrt{\frac{4}{27}}=\frac{sqrt{4}}{sqrt{27}}=\frac{2}{3sqrt{3}}=\frac{2sqrt{3}}{9}), (sqrt{\frac{15}{4}}=\frac{sqrt{15}}{sqrt{4}}=\frac{sqrt{15}}{2}), (sqrt{\frac{1}{12}}=\frac{sqrt{1}}{sqrt{12}}=\frac{1}{2sqrt{3}}=\frac{sqrt{3}}{6}), (sqrt{\frac{24}{49}}=\frac{sqrt{24}}{sqrt{49}}=\frac{2sqrt{6}}{7}), (sqrt{\frac{25}{48}}=\frac{sqrt{25}}{sqrt{48}}=\frac{5}{4sqrt{3}}=\frac{5sqrt{3}}{12})
The image shows a set of problems related to simplifying radical expressions, but without a clear indication of what needs to be solved. For example, we could simplify $\frac{\sqrt{12}}{\sqrt{25}}$, $\frac{\sqrt{8}}{\sqrt{9}}$ etc. based on the quotient rule for radicals, but we need to know which one is the focus.
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