Question

extension koalas rarely drink because they are able to get the water they need from eucalyptus leaves. suppose a koala eats 624.15 grams of eucalyptus leaves one day and 586.03 grams of eucalyptus leaves the next day. if the leaves the koala ate on the two days contained a total of 415.07 grams of water, what was the mass of the parts of the leaves that were not water?

Explanation:

Step1: Calculate total mass of leaves

First, find the total mass of eucalyptus leaves the koala ate in two days. Add the mass of leaves eaten on the first day (624.15 grams) and the second day (586.03 grams).
$$624.15 + 586.03 = 1210.18$$

Step2: Subtract water mass from total

Then, subtract the total mass of water (415.07 grams) from the total mass of leaves to find the mass of non - water parts.
$$1210.18 - 415.07 = 795.11$$

Answer:

795.11 grams