Question

factor completely.
$3j^5 + 4j^2 - 3j^4 - 4j^3$

Explanation:

Step1: Rearrange terms by degree

$3j^5 - 3j^4 - 4j^3 + 4j^2$

Step2: Group first/last two terms

$(3j^5 - 3j^4) + (-4j^3 + 4j^2)$

Step3: Factor out GCF from each group

$3j^4(j - 1) - 4j^2(j - 1)$

Step4: Factor out common binomial

$(j - 1)(3j^4 - 4j^2)$

Step5: Factor GCF from second term

$(j - 1)j^2(3j^2 - 4)$

Step6: Rewrite in standard order

$j^2(j - 1)(3j^2 - 4)$

Answer:

$j^2(j - 1)(3j^2 - 4)$