Question

factor the expression.
$x^2 + 22x + 121$
$x^2 + 22x + 121 = \square$

Explanation:

Step1: Identify perfect square form

The expression matches $a^2 + 2ab + b^2$, where $a=x$, $2ab=22x$, $b^2=121$.

Step2: Solve for $b$

Since $b^2=121$, $b=\sqrt{121}=11$. Verify $2ab=2*x*11=22x$, which matches.

Step3: Apply perfect square formula

$a^2 + 2ab + b^2=(a+b)^2$, substitute $a=x$, $b=11$.

Answer:

$(x+11)^2$