Question

factor by grouping. $5u^{3}+7u^{2}+30u + 42$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(5u^3 + 7u^2) + (30u + 42)$

Step2: Factor out the GCF from each group

Factor out $u^2$ from the first group and $6$ from the second group: $u^2(5u + 7) + 6(5u + 7)$

Step3: Factor out the common binomial factor

Factor out $(5u + 7)$ from both terms: $(5u + 7)(u^2 + 6)$

Answer:

$(5u + 7)(u^2 + 6)$