Question

factor by grouping.
$6b^2 - b + 24b - 4$
$(6b - ?)(\square b + \square)$

Explanation:

Step1: Group terms into pairs

Group first two and last two terms:
$(6b^2 - b) + (24b - 4)$

Step2: Factor out GCF from each pair

Factor $b$ from first group, 4 from second:
$b(6b - 1) + 4(6b - 1)$

Step3: Factor out common binomial

Factor $(6b - 1)$ from both terms:
$(6b - 1)(b + 4)$

Answer:

The missing values are 1, 1, and 4, so the fully factored form is $\boldsymbol{(6b - 1)(b + 4)}$