Question

1. factor by grouping, and check with distribution. 9x² + 3xy - 6x - 2y

Explanation:

Step1: Group the terms

$(9x^{2}+3xy)+(-6x - 2y)$

Step2: Factor out GCF from each group

$3x(3x + y)-2(3x + y)$

Step3: Factor out the common binomial factor

$(3x - 2)(3x + y)$

Step4: Check with distribution

$(3x-2)(3x + y)=3x\times3x+3x\times y-2\times3x - 2\times y=9x^{2}+3xy-6x - 2y$

Answer:

$(3x - 2)(3x + y)$