Question

the factor label method can be used to solve virtually any problem including changes in units. it is especially useful in making complex conversions dealing with concentrations and derived units. convert the following. 1. 35 ml = ____ dl 2. 950 g = __ kg 3. 275 mm = __ cm 4. 1,000 l = __ kl 5. 1,000 ml = __ l 6. 4,500 mg = __ g 7. 25 cm = __ mm 8. 0.005 kg = __ dag 9. 0.075 m = __ cm 10. 15 g = ____ mg

Explanation:

Step1: Recall volume conversion factor

1 dL = 100 mL, so 35 mL = 35÷100 dL = 0.35 dL

Step2: Recall mass conversion factor

1 kg = 1000 g, so 950 g = 950÷1000 kg = 0.95 kg

Step3: Recall length conversion factor

1 cm = 10 mm, so 275 mm = 275÷10 cm = 27.5 cm

Step4: Recall volume conversion factor

1 kL = 1000 L, so 1000 L = 1 kL

Step5: Recall volume conversion factor

1 L = 1000 mL, so 1000 mL = 1 L

Step6: Recall mass conversion factor

1 g = 1000 mg, so 4500 mg = 4500÷1000 g = 4.5 g

Step7: Recall length conversion factor

1 cm = 10 mm, so 25 cm = 25×10 mm = 250 mm

Step8: Recall mass conversion factor

1 dag = 0.1 kg, so 0.005 kg = 0.005÷0.1 dag = 0.05 dag

Step9: Recall length conversion factor

1 m = 100 cm, so 0.075 m = 0.075×100 cm = 7.5 cm

Step10: Recall mass conversion factor

1 g = 1000 mg, so 15 g = 15×1000 mg = 15000 mg

Answer:

1. 0.35 dL
2. 0.95 kg
3. 27.5 cm
4. 1 kL
5. 1 L
6. 4.5 g
7. 250 mm
8. 0.05 dag
9. 7.5 cm
10. 15000 mg