Question

a farmer has 3/4 of an acre to plant beans and squash. if 4/9 of an acre is planted with beans, how much is left for the squash? a) 1/5 of an acre b) 1/3 of an acre c) 11/36 of an acre d) 17/36 of an acre

Explanation:

Step1: Identify the total and used area

The total area for beans and squash is $\frac{3}{4}$ of an acre, and the area used for beans is $\frac{4}{9}$ of an acre. We need to find the remaining area for squash by subtracting the area used for beans from the total area.

Step2: Subtract the fractions

To subtract $\frac{4}{9}$ from $\frac{3}{4}$, we first find a common denominator. The least common denominator of 4 and 9 is 36. Convert the fractions: $\frac{3}{4}=\frac{3\times9}{4\times9}=\frac{27}{36}$ and $\frac{4}{9}=\frac{4\times4}{9\times4}=\frac{16}{36}$. Now subtract: $\frac{27}{36}-\frac{16}{36}=\frac{27 - 16}{36}=\frac{11}{36}$.

Answer:

C) 11/36 of an acre