Question

figure 3–76

1. a combination of inverters is shown in figure 3–77. if a high is applied to point a, determine the logic levels at points b through f.

a —▶◇ b —▶◇ c ●—▶◇ d —▶◇ e
●—▶◇ f

Explanation:

Step1: Invert A to get B

An inverter outputs the opposite logic level. Since A = HIGH, $B = \text{LOW}$

Step2: Invert B to get C

Invert the LOW level at B. $C = \text{HIGH}$

Step3: Invert C to get D

Invert the HIGH level at C. $D = \text{LOW}$

Step4: Invert D to get E

Invert the LOW level at D. $E = \text{HIGH}$

Step5: Invert C to get F

Invert the HIGH level at C. $F = \text{LOW}$

Answer:

• Point B: LOW
• Point C: HIGH
• Point D: LOW
• Point E: HIGH
• Point F: LOW