Question

in the figure below, m∠abd = 62°, and m∠2 is 2° more than m∠1. find m∠1.

Explanation:

Step1: Set up an equation

Let $m\angle1 = x$. Then $m\angle2=x + 2$. Since $m\angle ABD=m\angle1 + m\angle2$ and $m\angle ABD = 62^{\circ}$, we have the equation $x+(x + 2)=62$.

Step2: Simplify the left - hand side

Combining like terms in the equation $x+(x + 2)=62$, we get $2x+2 = 62$.

Step3: Solve for $x$

Subtract 2 from both sides of the equation $2x+2 = 62$: $2x=62 - 2=60$. Then divide both sides by 2: $x=\frac{60}{2}=30$.

Answer:

$30$