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Question
in the figure below, $\triangle opq$ is drawn. the line $\overleftrightarrow{ros}$ is drawn such that $\overleftrightarrow{ros} \parallel \overline{pq}$.
$\text{m}\angle opq = \text{m}\angle por$ because they are alternate interior angles.
$\text{m}\angle pqo = \quad$ because they are
Since $\overleftrightarrow{ROS} \parallel \overline{PQ}$, the angle corresponding to $\angle PQO$ is $\angle QOS$ (which is $x^\circ$). These two angles are alternate interior angles formed by the transversal $\overline{OQ}$ cutting the parallel lines $\overleftrightarrow{ROS}$ and $\overline{PQ}$.
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$\boldsymbol{m\angle PQO = m\angle QOS}$ because they are alternate interior angles