Question

in the figure below, the interior ray bisects the larger angle.
what is the value of x?

Explanation:

Step1: Use angle bisector property

Since ray DB bisects $\angle CDA$, $\angle CDB = \angle BDA$. So $\angle BDA = 50^\circ$.

Step2: Set up equation for bisected angle

The measure of $\angle BDA$ is given as $(2x)^\circ$, so:
$2x = 50$

Step3: Solve for x

Divide both sides by 2:
$x = \frac{50}{2}$

Answer:

25