Question

in the figure below, m∠wxz = 116°, and m∠2 is 44° more than m∠1. find m∠1. m∠1 = °

Explanation:

Step1: Set up an equation

Let $m\angle1 = x$. Then $m\angle2=x + 44^{\circ}$. Since $m\angle WXZ=m\angle1 + m\angle2$ and $m\angle WXZ = 116^{\circ}$, we have the equation $x+(x + 44^{\circ})=116^{\circ}$.

Step2: Simplify the equation

Combining like - terms, we get $2x+44^{\circ}=116^{\circ}$.

Step3: Solve for x

Subtract $44^{\circ}$ from both sides: $2x=116^{\circ}-44^{\circ}=72^{\circ}$. Then divide both sides by 2: $x = 36^{\circ}$.

Answer:

$36$