Question

fill in the blank question
a cars tires push on the ground with $-150\\ \text{n}$ of force forward. if the tires do not slip, then the ground pushes on the tires with $\boldsymbol{\square}$ n of force forward. if there are no other horizontal forces on the 1500 kg car, it will experience an acceleration of $\boldsymbol{\square}$ $\text{m/s}^2$ forward.

Explanation:

Step1: Apply Newton's Third Law

By Newton's third law, the force exerted by the ground on the tires is equal in magnitude and opposite in direction to the force the tires exert on the ground.
Since the tires push with $-150\ \text{N}$ forward, the ground pushes with $150\ \text{N}$ forward.

Step2: Apply Newton's Second Law

Use $F=ma$ to find acceleration, rearrange to $a=\frac{F}{m}$.
Substitute $F=150\ \text{N}$, $m=1500\ \text{kg}$:
$a=\frac{150}{1500}=0.1\ \text{m/s}^2$

Answer:

150; 0.1