Question

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solve the system of linear equations by substitution.
$y = - 2x + 6$
$2y - 3x = 5$
the solution is $(x,y)=(quad,quad).$

Explanation:

Step1: Isolate $y$ from first equation

$y = 6 - 2x$

Step2: Substitute $y$ into second equation

$2(6 - 2x) - 3x = 5$

Step3: Expand and simplify equation

$12 - 4x - 3x = 5 \\
12 - 7x = 5$

Step4: Solve for $x$

$-7x = 5 - 12 \\
-7x = -7 \\
x = 1$

Step5: Substitute $x=1$ into $y=6-2x$

$y = 6 - 2(1) = 4$

Answer:

$(1, 4)$