Question

fill in the blanks. then, choose the property of multiplication you used.
(a) (square\times1 = 5)
select (\boldsymbol{downarrow})
(b) (0\times9=square)
select (\boldsymbol{downarrow})
(c) (square\times9 = 9\times7)
select (\boldsymbol{downarrow})
(d) (2\times(5\times9)=(2\times5)\timessquare)
select (\boldsymbol{downarrow})

Explanation:

First sub - question (let's call it (a1)): $\square\times1 = 5$

Step 1: Recall the multiplication property

We know that for any number $a$, $a\times1=a$ and $1\times a = a$. So if we have $\square\times1 = 5$, by the identity property of multiplication (where the product of a number and 1 is the number itself), the number in the square should be 5 because $5\times1 = 5$.

Step 1: Recall the zero property of multiplication

The zero property of multiplication states that the product of any number and 0 is 0. So when we multiply 0 by 9, $0\times9 = 0$.

Step 1: Recall the commutative property of multiplication

The commutative property of multiplication states that for any two numbers $a$ and $b$, $a\times b=b\times a$. So if we have $\square\times9 = 9\times7$, by the commutative property, the number in the square should be 7 because $7\times9=9\times7$.

Answer:

5

Second sub - question ( (b) ): $0\times9=\square$