Question

fill in the empty spaces to complete the square. then write the probability of each offsprings phenotype (physical appearance) in the spaces to the right. express each probability as a fraction and as a percentage.

1. experiment: check that show statistics is turned on. be sure there are two ff ee parents. click breed until there are 500 offspring. write the results in the table below.

Explanation:

Step1: Count total genotypes

There are 16 boxes in the Punnett - square, so the total number of possible genotypes is 16.

Step2: Count genotypes for black fur, black eyes

Genotypes with at least one dominant 'F' for fur color and at least one dominant 'E' for eye color are: FFEE, FFEe, FfEE, FfEe. Counting them in the square, there are 9 such genotypes. So the fraction is $\frac{9}{16}$ and the percentage is $\frac{9}{16}\times100 = 56.25\%$.

Step3: Count genotypes for black fur, red eyes

Genotypes with at least one dominant 'F' for fur color and two recessive 'e's for eye color are: FFee, Ffee. There are 3 such genotypes. So the fraction is $\frac{3}{16}$ and the percentage is $\frac{3}{16}\times100 = 18.75\%$.

Step4: Count genotypes for white fur, black eyes

Genotypes with two recessive 'f's for fur color and at least one dominant 'E' for eye color are: ffEE, ffEe. There are 3 such genotypes. So the fraction is $\frac{3}{16}$ and the percentage is $\frac{3}{16}\times100 = 18.75\%$.

Step5: Count genotypes for white fur, red eyes

The genotype with two recessive 'f's for fur color and two recessive 'e's for eye color is:ffee. There is 1 such genotype. So the fraction is $\frac{1}{16}$ and the percentage is $\frac{1}{16}\times100 = 6.25\%$.

Answer:

Phenotype	Fraction	%
Black fur, red eyes	$\frac{3}{16}$	18.75
White fur, black eyes	$\frac{3}{16}$	18.75
White fur, red eyes	$\frac{1}{16}$	6.25