Question

fill in the missing values in the table for $f(x) = 2x - 4$.

$x$	$-2$	$0$	$2$	$4$	$6$
$f(x)$	$-8$	$-4$	$square$	$square$	$square$

Explanation:

Step1: Substitute \( x = 2 \) into \( f(x) = 2x - 4 \)

\( f(2) = 2\times2 - 4 = 4 - 4 = 0 \)

Step2: Substitute \( x = 4 \) into \( f(x) = 2x - 4 \)

\( f(4) = 2\times4 - 4 = 8 - 4 = 4 \)

Step3: Substitute \( x = 6 \) into \( f(x) = 2x - 4 \)

\( f(6) = 2\times6 - 4 = 12 - 4 = 8 \)

Answer:

For \( x = 2 \), \( f(x) = 0 \); for \( x = 4 \), \( f(x) = 4 \); for \( x = 6 \), \( f(x) = 8 \)

So the missing values in the table (from left to right) are \( 0 \), \( 4 \), \( 8 \)